Execution time linearSearch sort

The problem

Write a program that randomly generates an array of 100,000 integers and a key. Estimate the execution time of invoking the linearSearch method. Sort the array and estimate the execution time of invoking the binarySearch method. You can use the following code template to obtain the execution time:

long startTime = System.currentTimeMillis();
perform the task; 
long endTime = System.currentTimeMillis(); 
long executionTime = endTime - startTime;

Breaking it down

static final int SAMPLE_SIZE = 100000;

public static void main(String[] args) {

    int valueToSearch = (int) (Math.random() * SAMPLE_SIZE);

    Random random = new Random(10);
    int[] numbers = random.ints(0, 10).limit(SAMPLE_SIZE).toArray();

    System.out.println("Started linear search...");
    long start = System.currentTimeMillis();
    int index = linearSearch(numbers, valueToSearch);
    long finalTime = System.currentTimeMillis() - start;
    System.out.println("Finished linear search.");
    System.out.println("LinearSearch took: " + finalTime + " index = "
            + index);

    System.out.println("Sorting array...");
    start = System.currentTimeMillis();
    Arrays.stream(numbers).sorted();
    finalTime = System.currentTimeMillis() - start;
    System.out.println("Finished sorting.");
    System.out.println("Sorting took : " + finalTime);

    System.out.println("Performing binary search...");
    start = System.currentTimeMillis();
    int index2 = Arrays.binarySearch(numbers, valueToSearch);
    System.out.println("Finished binary search...");
    finalTime = System.currentTimeMillis() - start;
    System.out.println("Binary search took: " + finalTime + " index = "
            + index2);
}

public static int linearSearch(int[] numbers, int key) {

    for (int i = 0; i < numbers.length; i++) {
        if (numbers[i] == key)
            return i;
    }

    return -1;
}

Output

Started linear search...
Finished linear search.
LinearSearch took: 1 index = -1
Sorting array...
Finished sorting.
Sorting took : 1
Performing binary search...
Finished binary search...
Binary search took: 0 index = -100001